Skip to content
Calculator Collection
← All articles
chemical-engineeringJanuary 9, 2026

LMTD: How to Calculate the Log Mean Temperature Difference in a Heat Exchanger

Every heat exchanger lives or dies by one quantity: the temperature difference that pushes heat from the hot fluid into the cold one. But that difference is not constant. It is large where the fluids first meet and shrinks as they approach each other along the length of the exchanger. So which number do you put into your design equation? Not the inlet difference, not the outlet difference, and not the simple average of the two. The correct answer is the log mean temperature difference, or LMTD — the single effective driving force that captures how the temperature gap actually changes across the unit. This guide shows you how to calculate it and use it well.

What the LMTD Is and Why It Matters

The LMTD is the effective average temperature difference between the hot and cold streams in a heat exchanger, weighted to account for the way that difference varies exponentially along the flow path. It is the term that turns the basic heat-transfer design equation into something usable:

Q = U · A · LMTD

Here Q is the heat duty (how much energy you need to move per unit time), U is the overall heat-transfer coefficient (how readily heat crosses the wall between fluids), and A is the surface area available for transfer. The LMTD ties them together. Rearranged as A = Q / (U · LMTD), it tells you exactly how much area — and therefore how big and expensive — an exchanger must be to hit a target duty.

This matters because using the wrong temperature difference quietly wrecks a design. Substitute a simple arithmetic average and you will systematically overstate the driving force, undersize the area, and build an exchanger that cannot meet its duty in the field. The LMTD exists precisely because the temperature profile is curved, not linear, and getting it right is the difference between an exchanger that works and one that disappoints.

Why a Logarithmic Average and Not a Simple One

Picture a counterflow exchanger. The hot fluid enters at one end while the cold fluid enters at the other, and they flow in opposite directions. At each end you can measure a temperature difference:

  • ΔT₁ = (hot inlet) − (cold outlet), the gap at the hot end
  • ΔT₂ = (hot outlet) − (cold inlet), the gap at the cold end
Heat transfer at any point is proportional to the local temperature difference, and that difference decays exponentially as the fluids exchange energy. Averaging an exponential curve with a plain arithmetic mean overweights the high end. The logarithmic mean corrects for the curvature, giving the true average driving force across the whole surface. The result is always less than or equal to the arithmetic average, which is why skipping it makes an exchanger look more capable than it is.

How to Calculate the LMTD

The formula is:

LMTD = (ΔT₁ − ΔT₂) ÷ ln(ΔT₁ ÷ ΔT₂)

where ΔT₁ and ΔT₂ are the temperature differences at the two ends and ln is the natural logarithm. There is one special case: if ΔT₁ and ΔT₂ happen to be equal, the formula divides zero by zero, and the LMTD is simply that common value. Physically, equal end differences mean the gap never changes, so no averaging is needed.

Worked example. Suppose you are cooling a hot process stream with water in a counterflow exchanger:

  • Hot fluid in: 120 °C
  • Hot fluid out: 70 °C
  • Cold water in: 25 °C
  • Cold water out: 55 °C
First, find the two end differences:

1. ΔT₁ = 120 − 55 = 65 °C (hot end)

2. ΔT₂ = 70 − 25 = 45 °C (cold end)

Then apply the formula:

3. Numerator: 65 − 45 = 20

4. Ratio: 65 ÷ 45 = 1.444

5. ln(1.444) = 0.3677

6. LMTD = 20 ÷ 0.3677 ≈ 54.4 °C

Notice that the simple arithmetic average would have been (65 + 45) ÷ 2 = 55 °C — close here because the end differences are similar, but the gap widens fast when one end is much hotter than the other. You can run any set of temperatures instantly with the LMTD Heat Exchanger calculator rather than working the logarithm by hand.

Using the LMTD in Real Designs and Avoiding Mistakes

Once you have the LMTD, sizing follows directly. If your duty is 200 kW and your overall coefficient U is 500 W/m²·K, then A = Q / (U · LMTD) = 200,000 / (500 × 54.4) ≈ 7.4 m² of heat-transfer area. Change any temperature and the required area moves with it.

Match your ΔT pairing to the flow arrangement. In counterflow, pair hot-in with cold-out and hot-out with cold-in, as above. In parallel (co-current) flow, both fluids enter the same end, so you pair hot-in with cold-in and hot-out with cold-out. Mixing up the pairing is the most common LMTD error and produces a meaningless number.

Apply a correction factor for real shell-and-tube units. Pure counterflow is an idealization. Multi-pass shell-and-tube exchangers mix flow directions, so engineers multiply the LMTD by a correction factor F (always ≤ 1) read from standard charts. Forgetting F undersizes multi-pass designs.

Watch for a temperature cross. If the cold outlet rises above the hot outlet, a single counterflow pass cannot achieve it, and a naive calculation may even produce a negative argument inside the logarithm. That is a signal to rethink the configuration, not to ignore the math.

Keep your units consistent. Because LMTD is a difference of temperatures, a difference in °C equals the same difference in kelvin, so either works — but never mix Fahrenheit differences into an SI calculation.

Conclusion

The log mean temperature difference is the honest answer to a deceptively simple question: how hard is heat being pushed across the exchanger, on average? Because the temperature gap decays exponentially along the flow path, only a logarithmic average reflects reality, and only that number belongs in Q = U · A · LMTD. Pair your end differences correctly, apply a correction factor for multi-pass geometries, and treat the LMTD as the foundation on which the entire size, cost, and performance of the exchanger rests.

Key Takeaways

Know the formula: LMTD = (ΔT₁ − ΔT₂) ÷ ln(ΔT₁ ÷ ΔT₂), where ΔT₁ and ΔT₂ are the temperature differences at the two ends of the exchanger

Pair ends by flow type: In counterflow pair hot-in with cold-out; in parallel flow pair the two inlets — getting the pairing wrong invalidates the result

Use it to size: Feed the LMTD into A = Q ÷ (U · LMTD) with the LMTD Heat Exchanger calculator to find the heat-transfer area you need

Correct for reality: Multi-pass shell-and-tube exchangers need an F correction factor below 1, and a temperature cross signals the configuration must change

Looking for a calculator?

Calculator Collection has 4,000+ free calculators. Browse all calculators →